4(8+5v^2)=352

Solution for 4(8+5v^2)=352 equation:

4(8+5v^2)=352

We move all terms to the left:

4(8+5v^2)-(352)=0

We multiply parentheses

20v^2+32-352=0

We add all the numbers together, and all the variables

20v^2-320=0

a = 20; b = 0; c = -320;
Δ = b2-4ac
Δ = 02-4·20·(-320)
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160}{2*20}=\frac{-160}{40}
=-4
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160}{2*20}=\frac{160}{40}
=4
$